Satellite Orbits

Study Guide — EEEN 567: Satellite Engineering

Department of Electrical and Electronic Engineering, Egerton University

5th Year Undergraduate • Study Guide

Learning Objectives

By the end of this study guide, the student should be able to:

  1. Explain the fundamental principles governing satellite orbital motion, including Kepler's laws and Newton's law of gravitation.
  2. Classify satellite orbits by altitude and eccentricity into Low Earth Orbit (LEO), Medium Earth Orbit (MEO), Geostationary Earth Orbit (GEO), and Highly Elliptical Orbit (HEO).
  3. Compute orbital period, orbital velocity, and coverage characteristics for each orbit class using Kepler's third law.
  4. Describe the advantages, disadvantages, and representative applications of LEO, MEO, GEO, and HEO satellite systems.
  5. Compare the four orbit classes with respect to altitude, period, latency, coverage, launch energy, and typical missions.
  6. Select an appropriate orbit class for a given satellite mission and justify the selection.

Introduction

A satellite orbit is the trajectory followed by a satellite as it revolves around the Earth under the influence of gravity. The choice of orbit is one of the most fundamental decisions in satellite system design, because it determines almost everything about the mission: coverage area, revisit time, link budget, launch cost, orbital lifetime, radiation environment, and latency for communication systems.

Orbits are commonly classified along two dimensions:

Mission drives the orbit: Earth-observation satellites favour LEO for imaging resolution; navigation constellations (GPS) use MEO for global coverage with few satellites; broadcast and fixed satellite services favour GEO for permanent visibility of a ground region; and HEO serves high-latitude regions that GEO cannot cover well.
EARTH centre LEO MEO GEO Earth surface: r = R⊙ = 6,378 km LEO: r = 8,378 km (h = 2,000 km) MEO: r = 26,578 km (h = 20,200 km, GPS) GEO: r = 42,164 km (h = 35,786 km) r measured from Earth's centre scale: square-root compressed (not linear)

Fig. 1 — Concentric LEO, MEO and GEO orbit shells drawn at radial distance r from the Earth’s centre (altitude h = r − R⊙).

Orbital Mechanics Fundamentals

1. Newton's Law of Universal Gravitation

F = G · (Me m) / r2 G = 6.674×10-11 N·m²/kg², Me = 5.972×1024 kg, r = distance from Earth's centre (m)

2. Kepler's Laws of Planetary Motion (applied to satellites)

T = 2π √(a3 / μ),   where μ = GMe = 3.986×105 km3/s2 T = orbital period (s), a = semi-major axis from Earth's centre (km)

3. Circular Orbital Velocity (Vis-Viva for e = 0)

v = √(μ / r) r = a = Re + h (km), Re = 6,378 km, h = altitude above surface

4. Orbital Elements

Six classical orbital elements fully define an orbit: semi-major axis (a), eccentricity (e), inclination (i), right ascension of the ascending node (Ω), argument of perigee (ω), and true anomaly (ν). For this guide, altitude h = a − Re and eccentricity e are the most relevant.

Worked Example 1 — Orbital period of a 1,000 km orbit:
a = 6,378 + 1,000 = 7,378 km.  T = 2π√(7,378³ / 3.986×105) ≈ 6,307 s ≈ 105 min.
SECTION A — LOW EARTH ORBIT (LEO)

LEO: Low Earth Orbit

1. Definition and Key Parameters

LEO is the region of space from about 160 km up to 2,000 km above the Earth's surface. LEO is by far the most densely populated orbital regime, hosting the ISS, imaging satellites, and the new mega-constellations.

160–2,000 km
Altitude range
~90–127 min
Orbital period
~7.5–7.8 km/s
Orbital velocity
15–17 orbits/day
Revolutions
~20–40 min
Pass duration over a station
1–30 ms
One-way link latency

2. Characteristics

3. Representative Systems

SystemAltitudeInclinationPurpose
International Space Station (ISS)~420 km51.6°Scientific laboratory / crewed platform
Iridium NEXT~780 km86.4°Global mobile voice/data (66 sats)
Starlink~550 km53°/70°/97.6°Broadband internet mega-constellation
Planet Labs Dove / Landsat / Sentinel~500–770 kmSSO ~98°Earth observation / imaging
OneWeb~1,200 km87.4°Broadband constellation

Advantages

  • Low latency and path loss — small terminals, near real-time links
  • High imaging resolution for remote sensing
  • Cheapest orbit class to reach; highest payload mass fraction
  • Milder radiation environment

Disadvantages

  • Very short visibility per pass; continuous coverage needs many satellites
  • High relative velocity complicates tracking and handover
  • Atmospheric drag (lower LEO) limits lifetime without propulsion
  • Crowded regime — collision and debris risk is highest here
Special LEO variants: Sun-synchronous orbits (SSO) at ~600–900 km, inclination ~98°, precess ~1°/day so the satellite passes over a given latitude at the same local solar time — ideal for consistent imaging illumination. Polar orbits at i ≈ 90° give full global coverage over successive orbits.
SECTION B — MEDIUM EARTH ORBIT (MEO)

MEO: Medium Earth Orbit

1. Definition and Key Parameters

MEO occupies the altitude band between LEO and GEO, conventionally from about 2,000 km up to 35,786 km (below geostationary altitude). Its defining use today is satellite navigation.

2,000–35,786 km
Altitude range
~2–24 h
Orbital period
~3.9–7.0 km/s
Orbital velocity
~55–110 min
Pass duration
~70–130 ms
One-way link latency
Fewer than LEO
Satellites for global coverage

2. Characteristics

3. Representative Systems

SystemAltitudePlanes × SatsPeriod
GPS (USA)20,200 km6 × 24 (nominal)11 h 58 min
GLONASS (Russia)19,100 km3 × 2411 h 15 min
Galileo (EU)23,222 km3 × 27 (nominal)14 h 05 min
BeiDou (China)21,528 km (MEO) + IGSO/GEO27 MEO + others12 h 53 min (MEO)
O3b (SES) — "Other 3 billion"8,062 kmMEO communications constellation~4 h 52 min

Advantages

  • Global continuous coverage with only ~2 dozen satellites
  • Lower latency and path loss than GEO
  • Stable, slowly changing geometry — excellent for precise ranging/navigation

Disadvantages

  • Transit through Van Allen belts — radiation-hardening cost
  • Higher launch energy than LEO
  • Satellites pass overhead and set — still requires constellation + handover, unlike GEO
Worked Example 2 — Verify the GPS period:
a = 6,378 + 20,200 = 26,578 km.  T = 2π√(26,578³/3.986×105) = 43,080 s ≈ 11 h 58 min. ✓
SECTION C — GEOSTATIONARY EARTH ORBIT (GEO)

GEO: Geostationary Earth Orbit

1. Definition and Key Parameters

A satellite in GEO orbits at an altitude of exactly 35,786 km above the equator, in the equatorial plane (inclination = 0°), travelling west-to-east, with a period equal to the sidereal day (23 h 56 min 4 s). It therefore appears stationary over one point on the equator.

35,786 km
Altitude (exact)
23 h 56 min 4 s
Period (sidereal day)
3.075 km/s
Orbital velocity
0°
Inclination
~250 ms
Round-trip latency (up-down-up)
42.5% of globe
Coverage per satellite

2. Characteristics

3. Representative Systems

SystemService
Intelsat / SES / Eutelsat fleetsFixed satellite services, trunk telephony, TV distribution
DirecTV, DStv (Eutelsat/Multichoice)Direct-to-home broadcasting
GOES, Meteosat, HimawariMeteorological imaging (weather satellites)
Inmarsat / ThurayaMobile satellite services

Advantages

  • Appears fixed — no ground tracking; simple, cheap user terminals
  • Continuous coverage of a region; no handovers
  • Only 3 satellites for (almost) global coverage
  • Ideal for broadcast/multicast and real-time weather monitoring of fixed areas

Disadvantages

  • High path loss and large propagation delay (~250 ms RTT)
  • Poor coverage of polar/high-latitude regions
  • Most expensive orbit class to reach in energy terms
  • Congested orbital slot/spectrum coordination (ITU filings); eclipse seasons and station-keeping
Worked Example 3 — Derive GEO altitude:
Set T = 86,164 s (sidereal day): a = [μ(T/2π)²]1/3 = [3.986×105 × (86,164/2π)²]1/3 = 42,164 km. Hence h = 42,164 − 6,378 = 35,786 km. ✓
Related terms: Geosynchronous = same period as Earth's rotation but non-zero inclination/eccentricity (satellite traces an analemma/figure-8). Graveyard orbit = supersynchronous disposal orbit ~300 km above GEO. GEO belt = the ring of operational slots around the equator.
SECTION D — HIGHLY ELLIPTICAL ORBIT (HEO)

HEO: Highly Elliptical Orbit

1. Definition and Key Parameters

HEO refers to orbits with large eccentricity (typically e > 0.5), so that the satellite's altitude varies greatly between perigee (low) and apogee (high, often above GEO). Although the satellite spends most time near apogee (by Kepler's second law), when high it can dwell over a specific hemisphere for hours.

e > ~0.5
Typical eccentricity
~500–1,000 km
Perigee (Molniya)
~39,700 km
Apogee (Molniya)
11 h 58 min
Molniya period (half sidereal day)
63.4°
Critical inclination (no apsidal precession)
~8 h / 2 orbits
Continuous high-latitude coverage per sat

2. The Molniya Orbit

The classic HEO is the Molniya orbit, developed by the USSR: inclination 63.4° (the "critical inclination" at which Earth's oblateness does not rotate the line of apsides), period 11 h 58 min, perigee ~1,000 km over the southern hemisphere, apogee ~39,700 km over the northern hemisphere. The satellite spends ~8 of every 12 hours near apogee over the northern hemisphere. Three satellites give continuous coverage of high northern latitudes (Russia, Scandinavia, Canada) where GEO links are poor or impossible.

3. Representative Systems

SystemOrbitPurpose
Molniya / Meridian series (Russia)Molniya HEOMilitary & civil communications for high latitudes
Sirius XM radioTundra HEODigital radio broadcast to North America
INTEGRAL (ESA), Swift BAT?HEOAstronomy (long apogee dwell above radiation belts)

Advantages

  • Long dwell (hours) over high-latitude regions GEO cannot serve
  • Apogee altitude beyond GEO — large footprint and high elevation angles over target region
  • Lower launch energy than GEO for high-altitude operation over specific hemispheres
  • Useful for scientific missions (sampling magnetosphere at varying altitudes)

Disadvantages

  • Satellite speed and link geometry vary enormously over the orbit — complex link budget and tracking
  • Passes repeatedly through Van Allen belts (radiation damage)
  • Requires multiple satellites (2–3) for continuous service; complex ground tracking antennas
  • Perigee drag and perturbation management over long missions
Worked Example 4 — Molniya semi-major axis:
T = 11 h 58 min = 43,080 s ⇒ a = [μ(T/2π)²]1/3 = 26,578 km. Perigee rp = a(1−e), apogee ra = a(1+e). With rp ≈ 7,378 km (h≈1,000 km): e = 1 − 7,378/26,578 ≈ 0.72; ra = 26,578 × 1.72 &asymp 45,714 km from centre, i.e. ha &asymp 39,336 km. ✓

Comparison of Orbit Classes

PropertyLEOMEOGEOHEO (Molniya)
Altitude160–2,000 km2,000–35,786 km35,786 km (fixed)Perigee ~1,000 km → apogee ~39,700 km
Period~90–127 min~2–24 h23 h 56 min11 h 58 min
Velocity~7.8 km/s~3.9–7 km/s3.07 km/s1.5–10 km/s (varies)
Latency (1-way)1–30 ms~70–130 ms~125 ms~135 ms (at apogee)
Satellites for global coverageTens to thousands~20–303 (+ spares)2–3 per covered region
Ground trackingRequired, fastRequired, moderateNone (fixed dish)Required, moderate
Path lossLowestModerateHighestModerate/high (varies)
Launch energy (ΔV)~9.4 km/sHigher~12+ km/s (incl. GTO)Comparable to MEO
Orbital lifetimeMonths–years (drag)Decades~15 yr (station-keeping)Decades (with maintenance)
Radiation environmentMildVan Allen crossingsAbove belts (outer belt skirts)Repeated belt crossings
Typical missionsImaging, broadband constellations, ISS, IoTNavigation (GPS/Galileo/GLONASS/BeiDou), trunk commsBroadcasting, weather, fixed servicesHigh-latitude comms (Russia), broadcast (Tundra)
ExamplesISS, Starlink, Iridium, SentinelGPS, Galileo, O3bIntelsat, GOES, DStvMolniya, Meridian, Sirius XM

Orbit Selection Decision Guide

Interactive Orbital Calculator

Enter a circular-orbit altitude (or semi-major axis) to compute orbital period and velocity, and see which orbit class it belongs to. Try 550 km (Starlink), 20,200 km (GPS), or 35,786 km (GEO).


Summary of Key Points

  1. Orbit selection is mission-driven; the four principal classes are LEO, MEO, GEO, and HEO.
  2. LEO (160–2,000 km): cheap to reach, low latency and loss, high resolution — but needs constellations and suffers drag/debris.
  3. MEO (2,000–35,786 km): the navigation regime — ~24 satellites (GPS at 20,200 km, T = 11 h 58 min) give continuous global coverage with moderate latency.
  4. GEO (35,786 km, i = 0°, T = sidereal day): appears stationary; 3 satellites cover the globe except poles; high path loss and ~250 ms latency.
  5. HEO (e > 0.5; Molniya: i = 63.4°, T = 11 h 58 min): long apogee dwell over high latitudes, serving regions GEO cannot reach; only 3 satellites needed for continuous coverage.
  6. Kepler's third law (T = 2π√(a³/μ)) and the circular velocity (v = √(μ/r)) are the working tools for all orbit-class calculations.
  7. Trade-offs: altitude ↑ → coverage ↑, ground-terminal simplicity ↑, but latency, path loss, launch energy ↑ and imaging resolution ↓.

Review Questions

Q1. Using Kepler's third law, calculate the orbital period of a satellite in a circular orbit at 800 km altitude. What orbit class is it?
Show answera = 7,178 km; T = 2π√(7,178³/3.986×105) ≈ 6,011 s ≈ 100 min — LEO.
Q2. Why does a GEO satellite appear stationary to an earth station, and why is the orbit constrained to inclination 0°?
Show answerIts period equals the Earth's sidereal rotation period and it travels in the equatorial plane in the same sense as Earth's rotation, so its sub-satellite point stays fixed. Any inclination would trace a figure-8 (geosynchronous, not geostationary).
Q3. A mission requires continuous coverage of latitudes above 70°N. Why is GEO unsuitable, and which orbit class would you propose?
Show answerGEO elevation angles at 70°N are extremely low (<10°) and above ~81° GEO is not visible at all. HEO (Molniya, i = 63.4°) gives hours-long apogee dwell over the northern hemisphere with only 3 satellites; a polar LEO constellation is the alternative.
Q4. Explain why GPS satellites orbit at ~20,200 km with an ~12-hour period rather than in LEO or GEO.
Show answerMEO is a compromise: LEO would need many more satellites for continuous global geometry and would suffer rapid geometry change and higher drag; GEO gives poor geometry at high latitudes and cannot cover the poles. The half-sidereal-day period makes the constellation geometry repeat daily.
Q5. Derive the altitude of a geostationary orbit and state the value of the orbital velocity.
Show answerSet T = 86,164 s in a = [μ(T/2π)²]1/3 = 42,164 km; h = 35,786 km; v = √(μ/a) = 3.07 km/s.
Q6. Compare LEO and GEO mega-constellation vs. single-satellite approaches with respect to latency, terminal cost, and system complexity.
Show answerLEO: low latency (~ms) and low path loss → small cheap terminals, but needs hundreds–thousands of satellites, gateways, and inter-satellite links/handover — very high system complexity. GEO: single satellite, no tracking, but high latency (~250 ms RTT) and large terminals.

References and Further Reading